Pick up on 3.4 Switch
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/*
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*
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* Exercise 3-1. Our binary search makes two tests inside the loop, when one would
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* suffice (at the price of more tests outside). Write a version with only one test
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* inside the loop and measure the difference in run-time.
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*
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* Author: Kun Deng
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*/
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#include <stdio.h>
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#include <limits.h>
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#include <float.h>
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#define ARRAY_SIZE 99900000
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long v[ARRAY_SIZE];
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long binsearch(long x, long v[], long n);
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long binsearch_improved(long x, long v[], long n);
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void populate_array(const long size);
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void print_array(const long v[], long size);
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int main()
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{
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extern long v[];
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populate_array(ARRAY_SIZE);
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// print_array(v, ARRAY_SIZE);
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long x = 901103;
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printf("Starting binary search. Trying to find %ld...\n", x);
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long index = binsearch(x, v, ARRAY_SIZE);
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printf("Regular binary search complete\n");
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long index_improved = binsearch_improved(x, v, ARRAY_SIZE);
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printf("Improved binary search complete\n");
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if (index < 0)
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{
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printf("%ld was not found in the array\n", x);
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return -1;
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}
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printf("Binary search: Value %ld is at index %ld of the array\n", x, index);
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printf("Binary search improved: Value %ld is at index %ld of the array\n", x, index_improved);
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return 0;
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}
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long binsearch(long x, long v[], long n)
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{
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long low, mid, high;
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low = 0;
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high = n - 1;
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while (low <= high)
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{
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mid = (low + high) / 2;
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if (x < v[mid])
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{
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high = mid - 1;
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}
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else if (x > v[mid])
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{
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low = mid + 1;
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}
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else
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{
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return mid;
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}
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}
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return -1;
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}
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long binsearch_improved(long x, long v[], long n)
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{
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long low, mid, high;
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low = 0;
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high = n - 1;
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mid = (low + high) / 2;
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for (; (low <= high) && x != v[mid]; mid = (low + high) / 2)
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{
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if (x < v[mid])
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{
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high = mid - 1;
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}
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else
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{
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low = mid + 1;
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}
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}
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if (v[mid] == x)
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{
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return mid;
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}
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return -1;
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}
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void populate_array(long size)
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{
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extern long v[];
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long i = 0;
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v[i] = 1; // First element will start at 1
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for (i = 1; i != size; ++i)
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{
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long elem = v[i];
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v[i] = elem + (i * 2) + 1;
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}
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}
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void print_array(const long v[], long size)
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{
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printf("array is: ");
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for (long i = 0; i != size; ++i)
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{
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printf("%ld ", v[i]);
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}
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printf("\nWith %ld elements\n", size);
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}
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