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learning_c/ch_03/exercise_03-05/main.c
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C

/*
*
* Exercise 3-5. Write a function itob(n,s,b that converts the integer
* m into a base b character representation in the string s. In
* particular, itob(n,s,16) formats s as a hexadecimal integer in s.
*
*
* Author: Kun Deng
*/
#include <stdio.h>
#include "hex.h"
void test();
int main()
{
test();
return 0;
}
void test()
{
char *number = "21";
char hex_number[1024];
HexOctalConv_number_converted_to_hex(hex_number, number);
printf("%s converted to hex is %s\n", number, hex_number);
number = "55";
HexOctalConv_number_converted_to_hex(hex_number, number);
printf("%s converted to hex is %s\n", number, hex_number);
const int numerical_value = HexOctalConv_hex_converted_to_number(hex_number);
printf("Hexidecimal %s is %d\n", hex_number, numerical_value);
char octal_number[1024];
HexOctalConv_number_converted_to_octal(octal_number, number);
printf("%s converted to octal is %s\n", number, octal_number);
const int o_numberical_value = HexOctalConv_octal_converted_to_number(octal_number);
printf("Octal %s converted to a numerical value is %d\n", octal_number, o_numberical_value);
}